We all know that the distance between two points of the plane, with the coordinates of Cartesian P (x1, y1) and Q (x2, y2), is provided by the following formula:

https://www.varsitytutors.com/hotmath/hotmath_help/topics/magnitude-and-direction-of-vectors

The formula of distance is just the theorem of Pythagoras. For the evaluation of distance PQ between point P (x1, y1) and Q (x2, y2), first, make the right angle triangle which has the segment of PQ as the hypotenuse.

If the lengths of all the sides are p and q, then by the theorem of Pythagoras –

(PQ)^{2} = (PR)^{2} + (QR)^{2}

For solving the distance PQ, we have –

PQ = (PR)^{2} + (QR)^{2}

Since PR is the distance horizontally, it is just the difference between the coordinates of X – |(x2 – x1)|. Similarly, QR is the distance vertically |(y2 – y1). Since we square these distance and squares are non-negative, we need not worry about all these value signs.

https://www.sciencehq.com/mathematics/distance-formula.html

**Example 1: Find out the distance between the points P and Q.**

In the above example, we need –

P(x1, y1) = (-2, 0)

Q(x2, y2) = (3, 8)

Thus,

**Example 2: Find out the distance between the points A and B.**

A = (1,1) = (x1, y1)

B = (2,2) = (x2, y2)

**Example 3: Find the distance between points E and F.**

E= (1,2,3) = (x1, y1, z1)

F = (4,5,6) = (x2, y2, z2)